Given as 4x2 + 1 = 0
As we know, i2 = –1 ⇒ 1 = –i2
On substituting 1 = –i2 in the above equation, we get
4x2 – i2 = 0
(2x)2 – i2 = 0
[On using the formula, a2 – b2 = (a + b) (a – b)]
(2x + i) (2x – i) = 0
2x + i = 0 or 2x – i = 0
2x = –i or 2x = i
x = -i/2 or x = i/2
∴ The roots of the given equation are i/2, -i/2