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in Physics by (57.3k points)

A concave mirror produces three times magnified (enlarged) real image of an object placed at 10 cm in front of it. Where is the image located?

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M = \(\frac{Height\, of\, image}{Height\, of\, object}\)

\(\frac{h_1}{h_0}\) = \(\frac{-u}{v}\)

Let the height of object be h then height of image h = – 3h

\(\frac{3h}{h}\) = \(\frac{-v}{u}\) = \(\frac{v}{u}\) = 3

∴ Distance of object, u = – 10 cm

v = 3 × (10) = – 30 cm

Here – sign indicates, image is real and it is 30 cm in front of concave mirror.

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