
(a) vector B for X = vector B for Y
Both are oppositely directed hence net vector B = 0
(b) vector B due to X = vector B due to X both directed along Z–axis

(c) vector B due to X = vector B due to Y both directed opposite to each other.
Hence Net vector B = 0
(d) vector B due to X = vector B due to Y = 1 × 10–6T both directed along (–) ve Z–axis
Hence Net vector B = 2 × 1.0 × 10–6 = 2μT