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A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which is surmounted by another cylinder of height 60 cm and radius 8 cm. (Find the mass of the pole, given that 1 cm3 of iron has approximately 8g mass. (Use π = 3.14).

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Height of solid iron pole, h = 220 cm. 

Base diameter of pole, d = 24 cm. 

∴ Radius, r = 12 cm. 

Height of cylinder, h = 60 cm. 

Radius of cylinder, r= 8 cm. 

Mass of the pole = ? 

Volume of 1st Cylinder, V = πr2

= π × (12)2 × 220 

Volume of 2nd cylinder, V = πr2

= 77 × (8)2 × 60 

∴ Total Volume = π × (12)2 × 220 + π × (8)2 × 60 

= {144 × 220 + 64 × 60}π 

= 35520π 

= 111532.8 cm3

Mass of iron about 1 ccm is 8 gm. 

∴ Mass of iron 111532.8 ……. ?? 

\(= \frac{111532.8\times 8}{1000}kg\)

= 111.5328 × 8 kg. 

= 892.26 kg.

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