Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
5.6k views
in Compound Interest by (56.4k points)

The present population of a town is 25000. It grows at 4%, 5% and 8% during first year, second year and third year respectively. Find its population after 3 years.

1 Answer

+1 vote
by (30.6k points)
selected by
 
Best answer

Given details are,

Present population is = 25000

First year growth R1 = 4%

Second year growth R2 = 5%

Third year growth R3 = 8%

Number of years = 3

By using the formula,

A = P (1 + R/100)n

So, population after three years = P (1 + R1/100) (1 + R2/100) (1 + R3/100)

= 25000(1 + 4/100) (1 + 5/100) (1 + 8/100)

= 25000 (1.04) (1.05) (1.08)

= 29484

∴ Population after 3 years will be 29484.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...