Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
64.8k views
in Electric Potential by (57.3k points)

Derive an expression for potential due to charged spherical shell at following points (i) outer, (ii) at surface, (iii) inner point and also draw the graph for the variation of potential with the distance.

1 Answer

0 votes
by (61.2k points)
selected by
 
Best answer

Electric Potential due to Charged Spherical Shell: 

(a) At point P outside the shell (r > R)
When unit positive test charge is brought from infinity to point P, then the potential at P is equal to negative value of line integral of electric field between infinity and P.

Therefore, according to definition of potential

(b) On the surface of the charged spherical shell (r = R)
According to the definition of potential,

Where V is constant

(c) Inside the charged spherical shell (r < R)
According to the definition of potential

Dependence of electric field upon distance is different e.g. outside spherical shell
E = \(\frac{1}{4 \pi \varepsilon_{0}} \frac{q}{r^{2}} \hat{r}\)
and inside the shell E = 0.
Therefore the integration can be written as under,

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...