Question

Find the product:

(i) (4/7) × (14/25)

(ii) 7 (1/2) × 2 (4/15)

(iii) 3 (6/7) × 4 (2/3)

(iv) 6 (11/14) × 3 (1/2)

Answer 1

(i) Given (4/7) × (14/25)

(4/7) × (14/25) 

= (4 × 14)/ (7 × 25)

= (56/175)

Converting above fractions into simplest form

= (8/25)

(ii) Given 7 (1/2) × 2 (4/15)

We have convert mixed fractions into improper fractions

Then we get (15/2) and (34/15)

= 7 (1/2) × 2 (4/15) 

= (15/2) × (34/15)

= (15 × 34)/ (2 × 15)

= (510/30)

= 17

(iii) Given 3 (6/7) × 4 (2/3)

We have convert mixed fractions into improper fractions

Then we get (27/7) and (14/3)

= 3 (6/7) × 4 (2/3) 

= (27/7) × (14/3)

On simplifying

= 9 × 2

= 18

(iv) Given 6 (11/14) × 3 (1/2)

We have convert mixed fractions into improper fractions

Then we get (95/14) and (7/2)

6 (11/14) × 3 (1/2) 

= (95/14) × (7/2)

= (95 × 7)/28

= (665/28)

= 23 (3/4)