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in Alternating Current by (61.2k points)

An alternating source of Vrms = 120 V, f = 60 Hz is connected to an series circuit containing L = 200 mH, C = 40 µF and R = 20 Ω. Determine :
(i) total reactance
(ii) impedance
(iii) power factor
(iv) average power.

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Voltage (Vrms) = 120 V
and frequency (f) = 60 Hz
Inductance (L) = 200 mH = 200 × 10-3 H
Capacitance (C) = 40 µF = 40 × 10-6F
Resistance (R) = 20 Ω
Inductive reactance (XL) = ωL = 2πfL
= 2 × 3.14 × 60 × 200 × 10-3
= 75.36 Ω

\(\frac{120}{21.93}\) × 120 × 0.912
= 598.850 W

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