Given – 2(x2 – y2 + xy) – 3(x2 +y2 – xy)
Since the ‘–’ sign precedes the parentheses, we have to change the sign of each term in the parentheses when we remove them. Therefore, we have
= -2x2 + 2y2 – 2xy – 3x2 – 3y2 + 3xy
On rearranging,
= -2x2 – 3x2 + 2y2 – 3y2 – 2xy + 3xy
On simplifying, we get
= -5x2 – y2 + xy