Question

In Fig, ABCD is a rectangle with dimensions 32 m by 18 m. ADE is a triangle such that EF⊥ AD and EF= 14 cm. Calculate the area of the shaded region.

Answer 1

Given length of rectangle = 32m and breadth = 18m

We know that area of rectangle = length x breadth

Therefore area of the rectangle = AB x BC

= 32 m x 18 m

= 576 m²

Also given that base of triangle = 18m and height = 14m and EF⊥ AD

We know that area of triangle = ½ x base x height

Area of the triangle = ½ (AD x FE)

= ½ (BC x FE) [Since AD = BC]

= ½ (18 m x 14 m)

= 126 m²

Area of the shaded region = Area of the rectangle – Area of the triangle

= (576 – 126) m²

= 450 m²