Question

In sulphur estimation, 0.157 g of an organic compound gave 0.4813 g of barium sulphate. What is the percentage of sulphur in the compound?

Answer 1

Here, mass of the substance taken= 0.157g

Mass of BaSO₄ ppt. formed= 0.4813g

1 mole of BaSO₄ is equivalent to 1 g atom of S

(137+32+64)= 233g of BaSO₄=32g of S

0.4813g of BaSO₄ will contain sulphur=32/233*0.4813

% of sulphur in the compound= 32/233*0.4813*100/0.157

= 42.10