2x2 – 2√2 x + 1 = 0
Compare given equation with the general form of quadratic equation, which is ax2 + bx + c = 0
a = 2, b = – 2√2, c = 1
Find Discriminant:
D = b2 – 4ac
= (– 2√2)2 – 4 x 2 x 1
= 8 – 8
= 0
Equation has equal root.
Find roots:

x = \(\frac{1}{\sqrt2}\) or x = \(\frac{1}{\sqrt2}\)
Roots of equation are real.