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in Inverse of Matrix and Linear Equations by (48.0k points)

If matrix  A = \(\begin{bmatrix}1&-2&3\\[0.3em]1&2&1\\[0.3em]x&2&-3\end{bmatrix}\) is a singular matrix, then find x.

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⇒ (- 6 – 2) + 2(- 3 – x) + 3(2 – 2x) = 0

⇒ – 8 – 6 – 2x + 6 – 6x = 0

⇒ – 8 – 8x = 0

⇒ x = 8/-8

⇒ x = -1

⇒ Hence, x = -1

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