In the given figure,
A circle touches all the four sides of a quadrilateral ABCD whose sides are AB = 6 cm, BC = 9 cm and CD = 8 cm
Let P, Q, R and S are points where circle touches the sides AB, BC, CD and DA respectively.
Therefore,
AB + CD = BC + AD
6 + 8 = 9 + AD
14 = 9 + AD
AD = 14 – 9 = 5
Length of AD is 5 cm.