Since, tangents drawn from an external point are equally inclined to the line joining centre to that point.
Draw an image based on given instructions:

Here, PT is the tangent of the circle
OT ⊥ PT
And, ∠TPS = 60° (given)
∠TPO = 60°/2 = 30°
Now, from right ∆TPO:
sin 30° = OT/OP
1/2 = a/OP
or OP = 2a