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How many three-digit numbers can be generated from 1, 2, 3, 4, 5, 6, 7, 8, 9 such that the digits are in ascending order?

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How many three-digit numbers can be generated from 1, 2, 3, 4, 5, 6, 7, 8, 9 such that the digits are in ascending order?  

(a) 80 (b) 81 (c) 83 (d) 84

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(d) Any 3 numbers out of 9 can be selected in 9C3 ways. 

Now, these three numbers can be arranged among themselves in ascending order in only 1 way. 

Hence, total no. of ways = 9C3 × 1 = 84

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