Question

The area of a rectangle is 192 cm² and its perimeter is 56 cm. Find the dimensions of the rectangle.

Answer 1

The area of a rectangle is 192 cm² and its perimeter is 56 cm.

let l cm be the length and b cm be the breadth.

Area of rectangle = Length × Breadth

192 = l × b

⇨ l = 192/b ….(1)

Perimeter of rectangle = 2(length + breadth)

56 = 2(l + b)

from (1)

56 = 2(192/b + b)

28 = (192 + b²)/b

b²– 28b + 192 = 0

(b – 12 )(b – 16 ) = 0

b = 12 cm or b = 16 cm

Choose b = 12 cm then l = 16 cm

Hence, Length is 16 cm and Breadth is 12 cm.