From the figure we know that ∠COE and ∠DOF are vertically opposite angles
∠COE = ∠DOF = ∠z = 50o
From the figure we know that ∠BOD and ∠COA are vertically opposite angles
∠BOD = ∠COA = ∠t = 90o
We also know that ∠COA and ∠AOD form a linear pair
∠COA + ∠AOD = 180o
It can also be written as
∠COA + ∠AOF + ∠FOD = 180o
By substituting values in the above equation we get
90o + xo + 50o = 180o
On further calculation we get
xo + 140o = 180o
xo = 180o – 140o
By subtraction
xo = 40o
From the figure we know that ∠EOB and ∠AOF are vertically opposite angles
∠EOB = ∠AOF = x = y = 40
Therefore, the values of x, y, z and t are 40, 40, 50 and 90.