Centre of circle x2 + y2 = 16 is origin and radius is 4 unit.
Vertex of parabola y2 = 6x is origin. Common part of these curves is shown in figure.

Two curves intersect at point P and Q by solving equations, coordinates of these can be obtained.
Equation of curves x2 + y2 = 16 …..(i)
y2 = 6x …..(ii)

Thus coordinates of ponits P and Q are (2, 2√3) and (2, - 2√3).
Both the curves are symmetric about x-axis
∴ Required area = Area of OQAPO
= 2 x Area of ODAPO
= 2[Area of ODPO + Area of DAPD]

