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Find the area of the common region bounded by x2 + y2 = 16 and parabola y2 = 6x.

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Centre of circle x2 + y2 = 16 is origin and radius is 4 unit.

Vertex of parabola y2 = 6x is origin. Common part of these curves is shown in figure.

Two curves intersect at point P and Q by solving equations, coordinates of these can be obtained.

Equation of curves x2 + y2 = 16 …..(i)

y2 = 6x …..(ii)

Thus coordinates of ponits P  and Q are (2, 2√3) and (2, - 2√3).

Both the curves are symmetric about x-axis

∴ Required area = Area of OQAPO

= 2 x Area of ODAPO

= 2[Area of ODPO + Area of DAPD]

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