Question

For the reaction

C₁₂H₂₂O₁₁ H₂O  → (H+) C₆H₁₂O₆ + C₆H₁₂O₆

Write :

(i) Rate of reaction expression 

(ii) rate law equation

(iii) molecularity 

(iv) order of reaction

(b) The following data were obtained during the first order thermal decompostiotion of SO₂Cl₂ at constant volume-

SO₂Cl₂(g) → SO₂(g) + Cl₂(g)

Calculate the rate of reaction when total pressure is 0.65atm.

Answer 1

(a)

(i) Rate equation

(ii) Rate law equation

Rate = K[C₁₂H₂₂O₁₁]

(iii) Molecularity → 2

(iv) Order → first order

(b) As the reaction is of first order therefore

When

P₀ = 0.65atm i.e. P₀ + P = 0.65atm

P = 0.65 – P₀ = 0.65 – 0.50 = 0.15atm

Therefore the pressure of SO₂Cl₂ at time t(P_SO2Cl2) 

= P₀ – P = (0.50 – 0.15)atm = 0.35atm

Rate at that time = K × (P ) SO₂Cl₂

= 2.2316 × 10^–3 × 0.35

= 7.8 × 10^–4atm sec^–1