It is given that
Radius of the cone = 20cm = 0.2m
Height of the cone = 1m
We know that
Slant height l = √(r2 + h2)
By substituting the values
l = √ (0.22 + 12)
On further calculation
l = √(0.04 + 1) = √1.04
So we get
l = 1.02m
We know that
Curved surface area of cone = πrl
By substituting the values
Curved surface area of cone = 3.14 × 0.2 × 1.02
On further calculation
Curved surface area of cone = 0.64056 m2
So the curved surface area of 50 cones = 50 × 0.64056 = 32.028 m2
It is given that
Cost of painting = ₹ 25 per m2
So the cost of painting 32.028 m2 area = ₹ 25 × 32.028 = ₹ 800.70
Therefore, the cost of painting all these cones is ₹ 800.70.