Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
4.7k views
in Surface Areas And Volumes by (58.8k points)

A bus stop is barricaded from the remaining part of the road by using 50 hollow cones made of recycled cardboard. Each one has a base diameter of 40cm and height 1m. If the outer side of each of the cones is to be painted and the cost of painting is ₹ 25 per m2, what will be the cost of painting all these cones? (Use π = 3.14 and √1.04 = 1.02.)

1 Answer

+1 vote
by (44.3k points)
selected by
 
Best answer

It is given that

Radius of the cone = 20cm = 0.2m

Height of the cone = 1m

We know that

Slant height l = √(r2 + h2)

By substituting the values

l = √ (0.22 + 12)

On further calculation

l = √(0.04 + 1) = √1.04

So we get

l = 1.02m

We know that

Curved surface area of cone = πrl

By substituting the values

Curved surface area of cone = 3.14 × 0.2 × 1.02

On further calculation

Curved surface area of cone = 0.64056 m2

So the curved surface area of 50 cones = 50 × 0.64056 = 32.028 m2

It is given that

Cost of painting = ₹ 25 per m2

So the cost of painting 32.028 m2 area = ₹ 25 × 32.028 = ₹ 800.70

Therefore, the cost of painting all these cones is ₹ 800.70.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...