Question

Check the correctness of the relation:  \(Y = \frac{MgL}{\pi r^2 l}\) using the dimensional analysis.

Answer 1

The given relation, 
\(Y = \frac{MgL}{\pi r^2 l}\) .......(1)

Dimensional formula of L.H.S.= [M¹L^-1T^-2] and dimensional formula of R.H.S.

Since the dimensions of both the sides are the same, therefore the given relation (1) is “correct”.