Question

Find the products:

(-7/5)x²y × (3/2)xy² × (-6/5)x³y³

Answer 1

(-7/5)x²y × (3/2)xy² × (-6/5)x³y³

The coefficient of the product of two monomials is equal to the product of their coefficients.

The variable part in the product of two monomials is equal to the product of the variables in the given monomials.

Then,

= [(-7/5) × (3/2) × (-6/5)] × (x² × x × x³) × (y × y² × y³)

= [(-7×3×-6)/ (5×2×5)] × (x²⁺¹⁺³) × (y¹⁺²⁺³) … [∵ a^m × aⁿ = a^m+n]

= [(-7×3×-2)/ (5×1×5)] × (x⁶) × (y⁶)

= (63/25)x⁶y⁶