(2 + √2)2
= 22 + (√2)2 + 2 x 2 x √2 [using identity, (a+b)2 = a2 + b2 + 2ab]
= 4 + 2 + 4√2
= 6 + 4√2
Here, 6 is a rational number but 4√2 is an irrational number. Since, the sum of a rational and an irrational number is an irrational number, therefore, (2+ √2)2 is an irrational number.