Now, find the value of x by considering the given equation,=3 + 2x = 1 – x
Transposing 3 to RHS and it becomes -3 and -x to LHS it becomes x
= 2x + x = 1 – 3
= 3x = -2
Multiplying both side by (1/3)
= 3x × (1/3) = -2 × (1/3)
= x = (-2/3)
By substituting -2/3 in the place of x in given equation, we get
LHS,
= 3 + 2 × (-2/3)
= 3 + (-4/3)
= 3 – (4/3)
= (9 – 4) / 3
= 5/3
RHS,
= 1 – (-2/3)
= 1 + (2/3)
= (3 + 2)/ 3
= 5/3
By comparing LHS and RHS
= 5/3 = 5/3
∴ LHS = RHS
Hence, the result is verified.
