The above question can be written as,= 3x + 2x + 4 = 20 – 2x + 5
Now, find the value of x by considering the above equation,
= 5x + 4 = 20 – 2x + 5
Transposing 4 to RHS and it becomes -4 and -2x to LHS it becomes 2x
= 5x + 2x = 20 – 4 + 5
= 7x = 25 – 4
= 7x = 21
Multiplying both side by (1/7)
= 7x × (1/7) = 21 × (1/7)
= x = 21/7
= x = 3
By substituting 3 in the place of x in given equation, we get
LHS,
= 5x + 4
= 5 × (3) + 4
= 15 + 4
= 19
RHS,
= 20 – 2x + 5
= 20 – 2 × (3) + 5
= 20 – 6 + 5
= 25 – 6
= 19
By comparing LHS and RHS
= 19 = 19
∴ LHS = RHS
Hence, the result is verified.
