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Solve for x: x^2 – 4ax – b^2 + 4a^2 = 0.

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Solve for x: x2 – 4ax – b2 + 4a2 = 0.

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Given quadratic equation x2 – 4ax – b2 + 4a2 = 0

Comparing it by quadratic standard equation Ax2 + Bx + C = 0

A = 1, B = -4a and C = -(b2 – 4a2)

By Shridhar Acharya formula

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