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Prove that 2(cos^2 45° + tan^2 60°) – 6(sin^2 45° – tan^2 30°) = 6

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Prove that 2(cos2 45° + tan2 60°) – 6(sin2 45° – tan2 30°) = 6

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2(cos2 45° + tan2 60°) – 6(sin2 45° – tan2 30°)

= 7 – 1 = 6

Thus, 2(cos2 45° + tan2 60°) – 6(sin2 45° – tan2 30°) = 6

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