Question

If angle of elevation of sum is 45° then the length of the shadow casts by a 12 m high tree is :

(A) 6√3 m

(B) 12√3 m

(C) 12/√3 m

(D) 12 m

Answer 1

Answer is (D) 12 m

Let BC is a tree of height 12 m and shadow of tree AB = x m and angle of elevation of sun = 45°

i.e., ∠CAB = 45°

From right angled ΔABC,

tan 45° = BC/AB

⇒ 1 = 12/x

x = 12 m

Hence, length of shadow of tree = 12 m