Let AB is a flag-staff and BC is tower.
Let AB = x m and BC =h m. A point D which is 9 m away from the foot of tower C on the plane.
The angle of elevation of the top and the bottom of the flag-staff are 60° and 30° respectively.
Hence ∠ADC = 60° and ∠BDC = 30°

From right angled ∆BCD

Hence, height of tower = 3√3 m
Again from right angled ∆ACD,
tan 60° = AC/DC
⇒ √3 = (h + x)/9
⇒ h + x = 9√3
⇒ 3√3 + x = 9√3
⇒ x = 9√3 – 3√3
= 6√3 m
∴ Hence, height of flag-staff in 6√3 m.