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find the equation of circle with centre (3,4) and which touch the line 5x+12y+2=0

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find the equation of circle with centre (3,4) and which touch the line 5x+12y+2=0

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Perpendicular distance of the centre from the line  will be equal to the radius as the line is tangent to the circle

d = r = 61/13

So, the equation of circle will be

(x-3)2+(y-4)2 = (61/13)2

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