Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
912 views
in Surface Area and Volume by (31.2k points)
closed by

Eight spheres of same volumes are recasted by melting a metallic sphere with radius of 10 cm. Find the volume of the recasted sphere.

1 Answer

+1 vote
by (34.1k points)
selected by
 
Best answer

Given,

Radius of the metallic sphere (r) = 10 cm

∴ Volume of sphere = \(\frac { 4 }{ 3 }\)πr3

\(\frac { 4 }{ 3 }\) × π × r × (10)3

Let the radius of each recasted spheres be R.

∴ The volume of large sphere =8 × volume of spheres with radius R

Hence, radius of the sphere casted = 5 cm.

Surface area of sphere = 4πR2

= 4 × π × (5)2

=4 × π × 25

= 100π cm2

Hence, surface area of casted sphere = 100π cm2

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...