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There are 5 red marbles, 8 white marbles and 4 green marbles In a box. A marble is drawn at random from this box. Find the probability that the marble drawn is :

(i) red

(ii) white

(iii) not green.

1 Answer

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Best answer

Number of red marbles = 5

Number of white marbles = 8

and number of green marbles = 4

The total number of marbles in the box 

= 5 + 8 + 4 = 17.

When one marble is drawn from the box, then the total number of all possible outcomes = 17

(i) Let the probability of the red marble drawn be R.

∴ The number of favourable outcomes of event R = 5.

∴ P(R)

\(\frac { 5 }{ 17 }\)

(ii) The number of favourable outcomes of the white marble drawn (W) = 8.

∴ The probability that the marble drawn is white P(W)

\(\frac { 8 }{ 17 }\)

(iii) The number of favourable outcomes that the drawn marble is not green 

= 5 + 8 = 13.

∴ The probability that the marble drawn is not green.

Number of favourable out comes

\(\frac { 13 }{ 17 }\)

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