On the number line, in the figure, we have marked two points O and A representing numbers 0 and 1 respectively.
We draw AB = 1 unit ⊥r to the number line at A.
Now, join OB, we find that
OB = √(OA2 + AB2) = √(12 + 12) = √2
Now taking O as centre and radius OB = √2, we draw an are which intersect the number line at the point L.
We observe that OL = radius = √2.
Therefore, point L on the number line represents the irrational number √2.