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Locate √2 on the number line.

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On the number line, in the figure, we have marked two points O and A representing numbers 0 and 1 respectively.

We draw AB = 1 unit ⊥r to the number line at A.

Now, join OB, we find that

OB = √(OA2 + AB2) = √(12 + 12) = √2

Now taking O as centre and radius OB = √2, we draw an are which intersect the number line at the point L.

We observe that OL = radius = √2.

Therefore, point L on the number line represents the irrational number √2.

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