Question

Construct a triangle PQR in which PQ = 6 cm, ∠Q = 60° and QR + PR = 8 cm

Answer 1

Steps of construction:

1. Draw a line segment PQ = 6 cm as base line.
2. At Q, construct an angle of 60° and produce it.
3. From QY, cut off a line segment of length 8 cm and mark the point M.
4. Join PM.
5. Draw perpendicular bisector of PM, intersecting QM at R.
6. Join P to R.
7. Thus ∆PQR is the required triangle.