(c) (108–b)o
From the question it is given that, ∠1 = (2a + b)o and ∠6 = (3a – b)o
Since ∠5 and ∠6 these two forms a linear pair
Then,
∠5 = (180-3a + b)o … [equation 1]
∠5 = ∠1 = (180-3a + b)o [Because Corresponding angles] …equation (2)
On equating equation (1) and equation (2) we get,
2a + b = 180-3a + b
5a = 180
a = 360
Since ∠1 and ∠2 forms a linear pair so
∠2 = 1800– 2a-b