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Solve the equation \(\frac{8x+3}{2x-4} = \frac{4x}{x-5}\).

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⇒ \(\frac{8x+3}{2x-4} = \frac{4x}{x-5}\)

⇒ (8x + 3) (x – 5) = 4x (2x – x)

⇒ 8x2 – 40x + 3x – 15 = 8x2 – 16x

⇒ – 40x + 3x + 16x = 15

⇒ – 21x = 15

⇒ x = - 15/21

⇒ x = - 5/7

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