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Evaluate the integral: ∫sin 6x cos x dx

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It is given that

∫sin 6x cos x dx

Using the formula sin x × cos y = 1/2(sin(y + x) - sin(y - x))

∫sin 6x cos x dx = 1/2 ∫(sin 7x – sin (-5x)) dx

On further simplification

∫sin 6x cos x dx = 1/2 ∫sin 7x dx + 1/2 ∫sin 5x dx

By integrating w.r.t. x

∫ sin 6x cos x dx =

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