It is given that
∫sin 6x cos x dx
Using the formula sin x × cos y = 1/2(sin(y + x) - sin(y - x))
∫sin 6x cos x dx = 1/2 ∫(sin 7x – sin (-5x)) dx
On further simplification
∫sin 6x cos x dx = 1/2 ∫sin 7x dx + 1/2 ∫sin 5x dx
By integrating w.r.t. x
∫ sin 6x cos x dx =
