Question

A bag contains 8 red and 5 white balls. Two successive draws of 3 balls are made at random from the bag without replacements. Find the probability that the first draw yields 3 white balls and the second draw 3 red balls.

Answer 1

A = Drawing 3 white balls in the first draw. 

B = Drawing 3 red balls in the second draw.

Required Probability = P (A ∩ B) = P(A) . P(B/A)

Now,

After drawing 3 white balls in first draw 10 balls are left in bag, out of which 8 are red balls