Question

The vertices of a ∆ABC are A(3, 8), B(-1, 2) and C(6, -6). Find : 

(i) Slope of BC. 

(ii) Equation of a line perpendicular to BC and passing through A.

Answer 1

Vertices of a ∆ABC are A(3, 8), B(-1, 2) and C(6, -6)

Slope of the line perpendicular to BC = 7/8

(ii) Now, equation of the line perpendicular to BC and passing through A is

y - 8 = (7/8)(x - 3)

8y – 64 = 7x – 21 

7x – 8y + 43 = 0