Let ABCD is 100 m side square park and shaded region is 5 m wide park.
PQ = 100 -(5+5) = 90m
Area of ABCD = (side)2
= (100)2 sq. m = 10000 sq. m
Area of PQRS = (side)2
= (90)2 sq. m
= 8100 sq. m
∴ Area of path = (10000 – 8100) sq. m
= 1900 sq. m
10 m2 cementing = ₹250
∴ Expense on 1900 m2 cementing 250
= 250/10 x 1900
= ₹47,500