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1.8k views
in Real Numbers by (49.5k points)
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Prove that 3 + √5 is an irrational number.

1 Answer

+1 vote
by (48.8k points)
 
Best answer

Let us assume that 3 + √5 is a rational number. 

So, we can find co-prime integers ‘a’ and ‘b’ (b ≠ 0) such that

Since, a and b are integers, – 3 is a rational number and so √5 is a rational number. 

But this contradicts the fact that √5 is an irrational number. 

∴ Our assumption that 3 – √5 is a rational number is wrong. 

3 + √5 is an irrational number.

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