A dice is rolled once, the possible outcomes are 1, 2, 3, 4, 5 and 6.
Then,
The probability that the number on top will be
(a) Odd
Odd numbers in the dice are 1, 3, 5
Then,
Probability = total number of odd numbers/ Total number of outcomes
= 3/6 … [divide numerator and denominator by 3]
= ½
(b) Greater than 5
Greater than 5 is 6
Then,
Probability = total number Greater than 5/ Total number of outcomes
= 1/6
(c) A multiple of 3
Multiple of 3 = 3 and 6
Then,
Probability = total number of multiple of 3/ Total number of outcomes
= 2/6 … [divide numerator and denominator by 2]
= 1/3
(d) Less than 1
There is no number is less than 1.
So, probability of less than 1 = 0
(e) A factor of 36
Factors of 36 are 1, 2, 3, 4 and 6
Probability = total number of factor of 36/ Total number of outcomes
= 5/6
(f) A factor of 6
Factors of 6 are 1, 2, 3 and 6
Probability = total number of factor of 6/ Total number of outcomes
= 4/6 … [divide numerator and denominator by 2]
= 2/3
