Given: ABCD is a rectangle.
To prove: ABCD is a cyclic quadrilateral.
Proof:
⟂XBCD is a rectangle. [Given]
∴ ∠A = ∠B = ∠C = ∠D = 90° [Angles of a rectangle]
Now, ∠A + ∠C = 90° + 90°
∴ ∠A + ∠C = 180°
∴ ⟂ABCD is a cyclic quadrilateral. [Converse of cyclic quadrilateral theorem