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Prove that, any rectangle is a cyclic quadrilateral. 

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Given: ABCD is a rectangle. 

To prove: ABCD is a cyclic quadrilateral.

Proof:

XBCD is a rectangle. [Given] 

∴ ∠A = ∠B = ∠C = ∠D = 90° [Angles of a rectangle] 

Now, ∠A + ∠C = 90° + 90° 

∴ ∠A + ∠C = 180° 

ABCD is a cyclic quadrilateral. [Converse of cyclic quadrilateral theorem

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