Given: For road roller, diameter (d) = 0.9 m, length (h) = 1.4 m
To find: Area of a field pressed in 500 rotations
i. Since, area of field pressed in 1 rotation of road roller = curved surface area of road roller
∴ Curved surface area of the road roller = 2πrh
= πdh ,.. [∵ d = 2r]
= (22/7) x 0.9 x 1.47
= 22 x 0.9 x 0.2
= 3.96 sq.m.
ii. Area of land pressed in 1 rotation = 3.96 sq.m.
∴ Area of land pressed in 500 rotations
= 500 x 3.96 = 1980 sq.m.
∴ 1980 sq.m, land will be pressed in 500 rotations of the road roller.
