Question

Add: 3a(a-b-c), 2b (a-b + c)

Answer 1

The addition is as follows:

Here,

3a(a - b - c) = 3a² - 3ab - 3ac

2b(a - b + c) = 2ab - 2b² + 2bc

Hence the two polynomials to be added are 3a² - 3ab - 3ac and 2ab - 2b² + 2bc

3a(a - b - c) + 2b(a - b + c) = 3a² - 3ab - 3ac + 2ab - 2b² + 2bc = 3a² - ab - 3ac + 2bc - 2b²

The result is as follows: 3a² - ab - 3ac + 2bc - 2b²