Question

A battery of emf 10 V and internal resistance 3 Ω is connected to a resistor. The current in the circuit is. 0.5 A. The terminal voltage of the battery when the circuit is closed is

(a) 10 V 

(b) zero 

(c) 8.5 V 

(d) 1.5 V

Answer 1

(c) 8.5 V

V = ξ – Ir = 10 – (0.5 x 3) = 8.5 V.