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(1 - i/1 + i)^106 = a + ib then (a,b) is ... (a) (2, -1) (b) (1, 0) (c) (0, 1) (d) (-1, 2)

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(1 - i/1 + i)106 = a + ib then (a,b) is ...

(a) (2, -1) 

(b) (1, 0) 

(c) (0, 1) 

(d) (-1, 2)

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1 Answer

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by (49.5k points)

(b) The answer is (1, 0)

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