Question

An induced current of 2.5 mA flows through a single conductor of resistance 100 Ω. Find out the rate at which the magnetic flux is cut by the conductor.

Answer 1

Induced current, I = 2.5 mA 

Resistance of conductor, R = 100 Ω 

∴ The rate of change of flux, \(\frac{dΦ_B}{dt}\) = e

  \(\frac{dΦ_B}{dt}\) = e = IR = 2.5 x 10^-3 x 100 = 250 x 10^-3 dt

  \(\frac{dΦ_B}{dt}\) = 250 mWbs^-1