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How many unpaired electrons are present in CO^3+ , Fe^2+ ? Calculate their magnetic moment.

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How many unpaired electrons are present in CO3+ , Fe2+ ? Calculate their magnetic moment.

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CO (Z = 27) CO3+ [Ar] 3d6

Fe (Z = 26) Fe2+ [Ar] 3d6 

The number of unpaired electrons are 4 as follows:

Their magnetic moment is µ = \(\sqrt{4(4+2)}\) = \(\sqrt{24}\) = 4.89 µB

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